WAP in Java to accept an integer number N such that 0<N<27 Display the corresponding letter of the alphabet
import java.util.Scanner;
public class ATS{
public static void main(String[]args)
{
Scanner in = new Scanner(System.in);
System.out.print("Enter integer: ");
int n = in.nextInt();
if (n > 0 && n < 27)
{
char ch =(char)(n + 64);
System.out.println("Corresponding letter = " + ch);
}
else
{
System.out.println("Please enter a number in 1 to 26 range");
}
}
}
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